分式化简 [(x^2-4/x^2-4x+4)-(x-2/x+2)]/(x/x-2)

来源:学生作业帮助网 编辑:作业帮 时间:2024/07/12 22:39:37
分式化简 [(x^2-4/x^2-4x+4)-(x-2/x+2)]/(x/x-2)
xjA_%D* f>wvV[(;3;I6kqQPb*"R?" ^V|f-&Ѣ&7Ü0`!XoG[T)^hʄag # f@Pyrefh?d14( ,ìS.%"@FgV/HBX+#&9.F1a#|lGk_zo+N޿=?j=^GZ$ گq :|̟|_9UZCh6OO>w xK -VRhӵuөƲ,fp jZ f^M"W)VU!Zec]Mv % chWy `.I@Ę 3G>Ё\kL,fagY\!!*}񰍸 jIh, o&+S65׮M(Lx&τ9ؾ B_Sh M5 W!t9M3oMzTqnDDsǥKBK

分式化简 [(x^2-4/x^2-4x+4)-(x-2/x+2)]/(x/x-2)
分式化简 [(x^2-4/x^2-4x+4)-(x-2/x+2)]/(x/x-2)

分式化简 [(x^2-4/x^2-4x+4)-(x-2/x+2)]/(x/x-2)
{[(x²-4)/(x²-4x+4)]-(x-2)/(x+2)}/[x/(x-2)]
=[(x+2)(x-2)/(x-2)²-(x-2)/(x+2)][(x-2)/x]
=[(x+2)/(x-2)-(x-2)/(x+2)][(x-2)/x]
=[(x+2)/(x-2)][(x-2)/x]-[(x-2)/(x+2)][(x-2)/x]
=(x+2)/x-(x-2)²/x(x+2)
=[(x+2)²-(x-2)²]/x(x+2)
=[(x+2)-(x-2)][(x+2)+(x-2)]/x(x+2)
=8x/x(x+2)
=8/(x+2)
很高兴为您解答,【学习宝典】团队为您答题.
请点击下面的【选为满意回答】按钮,谢