初三关于反比例函数的问题如图,RT△ABO中,顶点A是双曲线y=k/x与直线y=-x-(k+1)在第四象限的交点,AB垂直x轴于点B,且△AOC的面积为1.5.求这两个函数的解析式.感觉有点难,难到根本不可能想出来.
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![初三关于反比例函数的问题如图,RT△ABO中,顶点A是双曲线y=k/x与直线y=-x-(k+1)在第四象限的交点,AB垂直x轴于点B,且△AOC的面积为1.5.求这两个函数的解析式.感觉有点难,难到根本不可能想出来.](/uploads/image/z/5855401-1-1.jpg?t=%E5%88%9D%E4%B8%89%E5%85%B3%E4%BA%8E%E5%8F%8D%E6%AF%94%E4%BE%8B%E5%87%BD%E6%95%B0%E7%9A%84%E9%97%AE%E9%A2%98%E5%A6%82%E5%9B%BE%2CRT%E2%96%B3ABO%E4%B8%AD%2C%E9%A1%B6%E7%82%B9A%E6%98%AF%E5%8F%8C%E6%9B%B2%E7%BA%BFy%3Dk%2Fx%E4%B8%8E%E7%9B%B4%E7%BA%BFy%3D-x-%28k%2B1%29%E5%9C%A8%E7%AC%AC%E5%9B%9B%E8%B1%A1%E9%99%90%E7%9A%84%E4%BA%A4%E7%82%B9%2CAB%E5%9E%82%E7%9B%B4x%E8%BD%B4%E4%BA%8E%E7%82%B9B%2C%E4%B8%94%E2%96%B3AOC%E7%9A%84%E9%9D%A2%E7%A7%AF%E4%B8%BA1.5.%E6%B1%82%E8%BF%99%E4%B8%A4%E4%B8%AA%E5%87%BD%E6%95%B0%E7%9A%84%E8%A7%A3%E6%9E%90%E5%BC%8F.%E6%84%9F%E8%A7%89%E6%9C%89%E7%82%B9%E9%9A%BE%2C%E9%9A%BE%E5%88%B0%E6%A0%B9%E6%9C%AC%E4%B8%8D%E5%8F%AF%E8%83%BD%E6%83%B3%E5%87%BA%E6%9D%A5.)
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