在三角形ABC的内部有一点P,且D,E,F是P分别以AB,BC,AC为对称轴的对称点,若△ABC的内角∠BAC=70°∠ABC=60∠BCA=50°,则∠ADB+∠BEC+∠CFA=
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![在三角形ABC的内部有一点P,且D,E,F是P分别以AB,BC,AC为对称轴的对称点,若△ABC的内角∠BAC=70°∠ABC=60∠BCA=50°,则∠ADB+∠BEC+∠CFA=](/uploads/image/z/5857815-39-5.jpg?t=%E5%9C%A8%E4%B8%89%E8%A7%92%E5%BD%A2ABC%E7%9A%84%E5%86%85%E9%83%A8%E6%9C%89%E4%B8%80%E7%82%B9P%2C%E4%B8%94D%2CE%2CF%E6%98%AFP%E5%88%86%E5%88%AB%E4%BB%A5AB%2CBC%2CAC%E4%B8%BA%E5%AF%B9%E7%A7%B0%E8%BD%B4%E7%9A%84%E5%AF%B9%E7%A7%B0%E7%82%B9%2C%E8%8B%A5%E2%96%B3ABC%E7%9A%84%E5%86%85%E8%A7%92%E2%88%A0BAC%3D70%C2%B0%E2%88%A0ABC%3D60%E2%88%A0BCA%3D50%C2%B0%2C%E5%88%99%E2%88%A0ADB%2B%E2%88%A0BEC%2B%E2%88%A0CFA%3D)
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