若√（tan^2x-sin^2x）=tanx*sinx则x取值范围

求证:Sin^2 x / (sinx-cosx) - (sin x + cos x)/(ta求证:Sin^2 x / (sinx-cosx) - (sin x + cos x)/(tan^2-1) = sin x + cos x 证明:(tan^2)x-(sin^2)x=(tan^2)x(sin^2)x 求证tan^x-sin^2x=tan^2x*sin^2x 已知tan=2,求(cos x+sin x)/(cos x-sin x)+sin^2x 证明tan^2x-sin^2x=tan^2 sin^2x 若√（tan^2x-sin^2x）=tanx*sinx则x取值范围 证明tan^θ-sin^2θ=tan^2θsin^2θ证明（1）tan^θ-sin^2θ=tan^2θsin^2θ（2）sin^4x+cos^4x=1-2sin^2cos^2x（31-tan^2x/1+tan^2x=cos^2x-sin^2x x∈（0,π/2）sin(x)+cos(x)=tan(x),x的范围? tan(x)=2求sin(x)cos(x)=? tan x=2,求 sin x * cos x=? 求证：tan x/2=sin x/(1+cos x) 求证：1-sin(x)=cos(x)*tan(x/2) sin(180+x)+cos(-x)/sin(180-x)+cos(360+x)=2 求tan(x+45） 已知:tan x=2 求:sin x+cos x/sin x-cos x=? tan(x+y)tan(x-y)=sin^2x-sin^2y/cos^2x-sin^2y 顺便问一下. tan,sin,cos是什么意思? (1+tan(x))/sin(2x)不定积分 若tan(x-π)=2,求2sin^2x+1/cos^2x-sin^2x的值若tan(x-π)=2,求2sin^2x+1/cos^2x-sin^2x的值 证(1/sin^2x)+(1/cos^2x)-(1/tan^2x)=2+tan^2x附加题（10分）：(1-sin^4x-cos^4x)/(sin^2x-sin^4x)