(1^4+1/4)*(3^4+1/4)*.(19^4+1/4)/(2^4+1/4)*(4^4+1/4).(20^4+1/4)等于多少(1^4+1/4)*(3^4+1/4)*.(19^4+1/4)/(2^4+1/4)*(4^4+1/4).(20^4+1/4)这个怎么样计算啊,怎么样计算呢,有什么简单的方法,这是在分式的通分 这一节出的题
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/06 16:35:26
![(1^4+1/4)*(3^4+1/4)*.(19^4+1/4)/(2^4+1/4)*(4^4+1/4).(20^4+1/4)等于多少(1^4+1/4)*(3^4+1/4)*.(19^4+1/4)/(2^4+1/4)*(4^4+1/4).(20^4+1/4)这个怎么样计算啊,怎么样计算呢,有什么简单的方法,这是在分式的通分 这一节出的题](/uploads/image/z/592455-39-5.jpg?t=%281%5E4%2B1%2F4%29%2A%283%5E4%2B1%2F4%29%2A.%2819%5E4%2B1%2F4%29%2F%282%5E4%2B1%2F4%29%2A%284%5E4%2B1%2F4%29.%2820%5E4%2B1%2F4%29%E7%AD%89%E4%BA%8E%E5%A4%9A%E5%B0%91%281%5E4%2B1%2F4%29%2A%283%5E4%2B1%2F4%29%2A.%2819%5E4%2B1%2F4%29%2F%282%5E4%2B1%2F4%29%2A%284%5E4%2B1%2F4%29.%2820%5E4%2B1%2F4%29%E8%BF%99%E4%B8%AA%E6%80%8E%E4%B9%88%E6%A0%B7%E8%AE%A1%E7%AE%97%E5%95%8A%2C%E6%80%8E%E4%B9%88%E6%A0%B7%E8%AE%A1%E7%AE%97%E5%91%A2%2C%E6%9C%89%E4%BB%80%E4%B9%88%E7%AE%80%E5%8D%95%E7%9A%84%E6%96%B9%E6%B3%95%2C%E8%BF%99%E6%98%AF%E5%9C%A8%E5%88%86%E5%BC%8F%E7%9A%84%E9%80%9A%E5%88%86+%E8%BF%99%E4%B8%80%E8%8A%82%E5%87%BA%E7%9A%84%E9%A2%98)
(1^4+1/4)*(3^4+1/4)*.(19^4+1/4)/(2^4+1/4)*(4^4+1/4).(20^4+1/4)等于多少(1^4+1/4)*(3^4+1/4)*.(19^4+1/4)/(2^4+1/4)*(4^4+1/4).(20^4+1/4)这个怎么样计算啊,怎么样计算呢,有什么简单的方法,这是在分式的通分 这一节出的题
(1^4+1/4)*(3^4+1/4)*.(19^4+1/4)/(2^4+1/4)*(4^4+1/4).(20^4+1/4)等于多少
(1^4+1/4)*(3^4+1/4)*.(19^4+1/4)/(2^4+1/4)*(4^4+1/4).(20^4+1/4)这个怎么样计算啊,
怎么样计算呢,有什么简单的方法,这是在分式的通分 这一节出的题目.大家帮想下,谢了
(1^4+1/4)*(3^4+1/4)*.(19^4+1/4)/(2^4+1/4)*(4^4+1/4).(20^4+1/4)等于多少(1^4+1/4)*(3^4+1/4)*.(19^4+1/4)/(2^4+1/4)*(4^4+1/4).(20^4+1/4)这个怎么样计算啊,怎么样计算呢,有什么简单的方法,这是在分式的通分 这一节出的题
x^4+1/4=x^4+x^2+1/4-x^2=(x^2+1/2)^2-x^2)
=(x^2+1/2+x)(x^2+1/2-x)=(x+1/2)^2+1/4)(x-1/2)^2+1/4)
即得x^4+1/4=(x+1/2)^2+1/4)(x-1/2)^2+1/4)
(1^4+1/4)*(3^4+1/4)*.(19^4+1/4)/(2^4+1/4)*(4^4+1/4).(20^4+1/4)
={((1/2)^2+1/4)((3/2)^2+1/4)((5/2)^2+1/4)((7/2)^2+1/4)...((37/2)^2+1/4)((39/2)^2+1/4)}/{((3/2)^2+1/4)((5/2)^2+1/4)((7/2)^2+1/4)((9/2)^2+1/4)...((39/2)^2+1/4)((41/2)^2+1/4)}
=((1/2)^2+1/4)/((41/2)^2+1/4)=2/(41^2+1)=1/841
可以用计算机找规律 我数学也不好
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