三道高一函数题1 函数y=f(x)的定义域为【-2,4】,则函数g(x)=f(x)+f(-x)的定义域为2 已知x属于【0,1】,则函数y=根号(x+2)- 根号(1-x)的值域是 3 已知二次函数f(x)满足条件f(0)=1,f(x+1)=f(x)+2x,求f(x)
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![三道高一函数题1 函数y=f(x)的定义域为【-2,4】,则函数g(x)=f(x)+f(-x)的定义域为2 已知x属于【0,1】,则函数y=根号(x+2)- 根号(1-x)的值域是 3 已知二次函数f(x)满足条件f(0)=1,f(x+1)=f(x)+2x,求f(x)](/uploads/image/z/5926784-32-4.jpg?t=%E4%B8%89%E9%81%93%E9%AB%98%E4%B8%80%E5%87%BD%E6%95%B0%E9%A2%981+%E5%87%BD%E6%95%B0y%3Df%28x%29%E7%9A%84%E5%AE%9A%E4%B9%89%E5%9F%9F%E4%B8%BA%E3%80%90-2%2C4%E3%80%91%2C%E5%88%99%E5%87%BD%E6%95%B0g%28x%29%3Df%28x%29%2Bf%28-x%29%E7%9A%84%E5%AE%9A%E4%B9%89%E5%9F%9F%E4%B8%BA2+%E5%B7%B2%E7%9F%A5x%E5%B1%9E%E4%BA%8E%E3%80%900%2C1%E3%80%91%2C%E5%88%99%E5%87%BD%E6%95%B0y%3D%E6%A0%B9%E5%8F%B7%EF%BC%88x%2B2%29-+%E6%A0%B9%E5%8F%B7%EF%BC%881-x%EF%BC%89%E7%9A%84%E5%80%BC%E5%9F%9F%E6%98%AF+3+%E5%B7%B2%E7%9F%A5%E4%BA%8C%E6%AC%A1%E5%87%BD%E6%95%B0f%28x%29%E6%BB%A1%E8%B6%B3%E6%9D%A1%E4%BB%B6f%280%29%3D1%2Cf%28x%2B1%29%3Df%28x%29%2B2x%2C%E6%B1%82f%28x%29)
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