有一在空气中暴露过的KOH的样品,经分析测知其含水 7.62%,含K2CO3 2.38%KOH 90%,若将此样品加入73g 10%的盐酸中,再用10.2%的KOH溶液中和过量的酸,则蒸发中和后的溶液所得的固体的质量约为( )g
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/10 19:10:49
![有一在空气中暴露过的KOH的样品,经分析测知其含水 7.62%,含K2CO3 2.38%KOH 90%,若将此样品加入73g 10%的盐酸中,再用10.2%的KOH溶液中和过量的酸,则蒸发中和后的溶液所得的固体的质量约为( )g](/uploads/image/z/6069595-67-5.jpg?t=%E6%9C%89%E4%B8%80%E5%9C%A8%E7%A9%BA%E6%B0%94%E4%B8%AD%E6%9A%B4%E9%9C%B2%E8%BF%87%E7%9A%84KOH%E7%9A%84%E6%A0%B7%E5%93%81%2C%E7%BB%8F%E5%88%86%E6%9E%90%E6%B5%8B%E7%9F%A5%E5%85%B6%E5%90%AB%E6%B0%B4+7.62%25%2C%E5%90%ABK2CO3+2.38%25KOH+90%25%2C%E8%8B%A5%E5%B0%86%E6%AD%A4%E6%A0%B7%E5%93%81%E5%8A%A0%E5%85%A573g+10%25%E7%9A%84%E7%9B%90%E9%85%B8%E4%B8%AD%2C%E5%86%8D%E7%94%A810.2%25%E7%9A%84KOH%E6%BA%B6%E6%B6%B2%E4%B8%AD%E5%92%8C%E8%BF%87%E9%87%8F%E7%9A%84%E9%85%B8%2C%E5%88%99%E8%92%B8%E5%8F%91%E4%B8%AD%E5%92%8C%E5%90%8E%E7%9A%84%E6%BA%B6%E6%B6%B2%E6%89%80%E5%BE%97%E7%9A%84%E5%9B%BA%E4%BD%93%E7%9A%84%E8%B4%A8%E9%87%8F%E7%BA%A6%E4%B8%BA%EF%BC%88+%EF%BC%89g)
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