一道关于截长补短的三角形几何题如图,在△ABC中AB=AC,∠ABD=60°,∠ADB=90°-1/2∠BAC.求证:AB=BD+DC.
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![一道关于截长补短的三角形几何题如图,在△ABC中AB=AC,∠ABD=60°,∠ADB=90°-1/2∠BAC.求证:AB=BD+DC.](/uploads/image/z/6097372-52-2.jpg?t=%E4%B8%80%E9%81%93%E5%85%B3%E4%BA%8E%E6%88%AA%E9%95%BF%E8%A1%A5%E7%9F%AD%E7%9A%84%E4%B8%89%E8%A7%92%E5%BD%A2%E5%87%A0%E4%BD%95%E9%A2%98%E5%A6%82%E5%9B%BE%2C%E5%9C%A8%E2%96%B3ABC%E4%B8%ADAB%3DAC%2C%E2%88%A0ABD%3D60%C2%B0%2C%E2%88%A0ADB%3D90%C2%B0-1%2F2%E2%88%A0BAC.%E6%B1%82%E8%AF%81%EF%BC%9AAB%3DBD%2BDC.)
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