详见补充.一、如图①,△ABC中,∠B=60°,△ABC的角平分线AD,CE交于点O.求证:AE+CD=AC二、如图②,△ABC中,∠BAC=60°,∠ACB=40°,AD、BE分别平分∠BAC、∠ABC.求证:AE+BE=AB+BD.图一上点O忘了标了,
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![详见补充.一、如图①,△ABC中,∠B=60°,△ABC的角平分线AD,CE交于点O.求证:AE+CD=AC二、如图②,△ABC中,∠BAC=60°,∠ACB=40°,AD、BE分别平分∠BAC、∠ABC.求证:AE+BE=AB+BD.图一上点O忘了标了,](/uploads/image/z/6116037-69-7.jpg?t=%E8%AF%A6%E8%A7%81%E8%A1%A5%E5%85%85.%E4%B8%80%E3%80%81%E5%A6%82%E5%9B%BE%E2%91%A0%2C%E2%96%B3ABC%E4%B8%AD%2C%E2%88%A0B%3D60%C2%B0%2C%E2%96%B3ABC%E7%9A%84%E8%A7%92%E5%B9%B3%E5%88%86%E7%BA%BFAD%2CCE%E4%BA%A4%E4%BA%8E%E7%82%B9O.%E6%B1%82%E8%AF%81%EF%BC%9AAE%2BCD%3DAC%E4%BA%8C%E3%80%81%E5%A6%82%E5%9B%BE%E2%91%A1%2C%E2%96%B3ABC%E4%B8%AD%2C%E2%88%A0BAC%3D60%C2%B0%2C%E2%88%A0ACB%3D40%C2%B0%2CAD%E3%80%81BE%E5%88%86%E5%88%AB%E5%B9%B3%E5%88%86%E2%88%A0BAC%E3%80%81%E2%88%A0ABC.%E6%B1%82%E8%AF%81%EF%BC%9AAE%2BBE%3DAB%2BBD.%E5%9B%BE%E4%B8%80%E4%B8%8A%E7%82%B9O%E5%BF%98%E4%BA%86%E6%A0%87%E4%BA%86%EF%BC%8C)
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