抛物线运动轨迹问题!如图,曲线ABC为抛物线的一部分,是一个作直线运动的质点的位置随时间变化的关系曲线.曲线在A点处切线与x轴夹角为45°请问为什么T=0时,速度V=1m/s?
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/11 19:27:05
![抛物线运动轨迹问题!如图,曲线ABC为抛物线的一部分,是一个作直线运动的质点的位置随时间变化的关系曲线.曲线在A点处切线与x轴夹角为45°请问为什么T=0时,速度V=1m/s?](/uploads/image/z/6207370-34-0.jpg?t=%E6%8A%9B%E7%89%A9%E7%BA%BF%E8%BF%90%E5%8A%A8%E8%BD%A8%E8%BF%B9%E9%97%AE%E9%A2%98%21%E5%A6%82%E5%9B%BE%2C%E6%9B%B2%E7%BA%BFABC%E4%B8%BA%E6%8A%9B%E7%89%A9%E7%BA%BF%E7%9A%84%E4%B8%80%E9%83%A8%E5%88%86%2C%E6%98%AF%E4%B8%80%E4%B8%AA%E4%BD%9C%E7%9B%B4%E7%BA%BF%E8%BF%90%E5%8A%A8%E7%9A%84%E8%B4%A8%E7%82%B9%E7%9A%84%E4%BD%8D%E7%BD%AE%E9%9A%8F%E6%97%B6%E9%97%B4%E5%8F%98%E5%8C%96%E7%9A%84%E5%85%B3%E7%B3%BB%E6%9B%B2%E7%BA%BF%EF%BC%8E%E6%9B%B2%E7%BA%BF%E5%9C%A8A%E7%82%B9%E5%A4%84%E5%88%87%E7%BA%BF%E4%B8%8Ex%E8%BD%B4%E5%A4%B9%E8%A7%92%E4%B8%BA45%C2%B0%E8%AF%B7%E9%97%AE%E4%B8%BA%E4%BB%80%E4%B9%88T%3D0%E6%97%B6%2C%E9%80%9F%E5%BA%A6V%3D1m%2Fs%3F)
xnAoIzafYbjfgXʪ]xDZJ
BB,$^И7LQ;`KXפc?>
;=`͛s_f
os
3;h9q8?#y4%w/
97i9%=A#tg ?4TxgMiV 휍Tyv__x(~hq#s%F,K`sEP0xu]6V.in1?jE=ڏLo-2YHwʪV)O?