先化简,再求值∶(1/x-y-1/x+y)÷2y/x²+2xy+y²,其中x=根号下3加根号下2,y=根号下3-
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先化简,再求值∶(1/x-y-1/x+y)÷2y/x²+2xy+y²,其中x=根号下3加根号下2,y=根号下3-
先化简,再求值∶(1/x-y-1/x+y)÷2y/x²+2xy+y²,其中x=根号下3加根号下2,y=根号下3-
先化简,再求值∶(1/x-y-1/x+y)÷2y/x²+2xy+y²,其中x=根号下3加根号下2,y=根号下3-
(1/x-y-1/x+y)÷2y/x²+2xy+y²
=[2y/(x+y)(x-y) ]/[(2y)/(x+y)(x+y)]
=(x+y)/(x-y)
又x=根号3+根号2,y=根号3-根号2
所以x+y=2倍的根号3,x-y=2倍的根号2
所以原式=根号3/根号2=根号6/2
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