高二数学直线与圆锥曲线设A,B分别是直线y=2√(5)/5x和y=-2√(5)/5x上的两个动点,并且向量/AB/=2√5,动点P满足向量OP=向量OA+向量OB.记动点P的轨迹为C1,求椭圆C的方程为什么 :令A(t,2t/√5) B(s,-
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![高二数学直线与圆锥曲线设A,B分别是直线y=2√(5)/5x和y=-2√(5)/5x上的两个动点,并且向量/AB/=2√5,动点P满足向量OP=向量OA+向量OB.记动点P的轨迹为C1,求椭圆C的方程为什么 :令A(t,2t/√5) B(s,-](/uploads/image/z/6553650-66-0.jpg?t=%E9%AB%98%E4%BA%8C%E6%95%B0%E5%AD%A6%E7%9B%B4%E7%BA%BF%E4%B8%8E%E5%9C%86%E9%94%A5%E6%9B%B2%E7%BA%BF%E8%AE%BEA%2CB%E5%88%86%E5%88%AB%E6%98%AF%E7%9B%B4%E7%BA%BFy%3D2%E2%88%9A%EF%BC%885%EF%BC%89%2F5x%E5%92%8Cy%3D-2%E2%88%9A%EF%BC%885%EF%BC%89%2F5x%E4%B8%8A%E7%9A%84%E4%B8%A4%E4%B8%AA%E5%8A%A8%E7%82%B9%2C%E5%B9%B6%E4%B8%94%E5%90%91%E9%87%8F%2FAB%2F%3D2%E2%88%9A5%2C%E5%8A%A8%E7%82%B9P%E6%BB%A1%E8%B6%B3%E5%90%91%E9%87%8FOP%3D%E5%90%91%E9%87%8FOA%2B%E5%90%91%E9%87%8FOB.%E8%AE%B0%E5%8A%A8%E7%82%B9P%E7%9A%84%E8%BD%A8%E8%BF%B9%E4%B8%BAC1%2C%E6%B1%82%E6%A4%AD%E5%9C%86C%E7%9A%84%E6%96%B9%E7%A8%8B%E4%B8%BA%E4%BB%80%E4%B9%88+%EF%BC%9A%E4%BB%A4A%28t%2C2t%2F%E2%88%9A5%29+B%28s%2C-)
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