作业帮化简：sin^2a*tana+cos^2a/tana+2sina*cosa
来源：学生作业帮助网 编辑：作业帮 时间：2024/11/17 17:47:57
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化简：sin^2a*tana+cos^2a/tana+2sina*cosa
化简：sin^2a*tana+cos^2a/tana+2sina*cosa
化简：sin^2a*tana+cos^2a/tana+2sina*cosa
sin^2a*tana+cos^2a/tana+2sina*cosa
=(1-cos^2a)*tana+(1-sin^2a)/tana+2sina*cosa
=tana-sina*cosa+1/tana-sina*cosa+2sina*cosa
=tana+1/tana
sin²a*tana+cos²a/tana+2sina*cosa
=sin³a/cosa+cos³a/sina+2sina*cosa
=(sin^4a+cos^4a+2sin²acos²a)/(sinacosa)
=2(sin²a+cos²a)²/sin(2a)
=2/sin(2a)
化简sin²a*tana+cos²acota+2sinacosa
化简：sin^2a*tana+cos^2a/tana+2sina*cosa
证明cos^4 a-sin^4 a=cos^2(1-tana)(1+tana)
证明sin^4 a+cos^4 a=cos^2(1-tana)(1+tana)
tana=2,求sin^2a-cos^2a
tana=2 sin^a+2cos^2a=?
(cota-tana)/(sin^2a-cos^2a)+(seca/sina)化简（cota-tana）/(sin^2a-cos^2a)+(seca/sina)
化简1.（sina-cosa）² 2.sin a/2cos a/2 3.cos四次方a -sin四次方a 4.1/1-tana -1/1+tana
[3sin^2 (a/2)-2sin(a/2)cos(a/2)+cos^2 (a/2)]/[tana+1/tana]
求证sin^2a*tana+cos^2a*1/tana+2sina*cosa=tana+1/tana
化简[tan(-a-π)*sin(2π+a)]/[cos(-a)*tana]
(sin(-a-π)-tan(-a)+cot(π/2+a))/((tana-π)+cos(π-a)+sin((3π)/2+a)) 化简
求证1+2sina cosa/sin^2a-cos^2a=tana+1/tana-1
求证：1+2sina cosa /sin^2a -cos^2a = tana +1/tana -1.
(1-2sinAcosA)/(cos^2A-sin^2A)=(1-tanA)/(1+tanA)
证明(1-2sinAcosA)/(cos^2A-sin^2A)=(1-tanA)/(1+tanA)
求证：(1-tana)/(1+tana)=(1-2sinacosa)/(cos^2×a-sin^2×a)
cos^2a-sin^2a/1+2sinacosa=1-tana/1+tana怎么证明?