已知点A(0,二分之根号15),B(1/2,0),以线段AB为边,在第一象限内作正三角形ABC.如下接上:直线y=kx+b过点C,与x轴,y轴分别交于D,E,且DE平行于AB求线段OE及BD的长
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![已知点A(0,二分之根号15),B(1/2,0),以线段AB为边,在第一象限内作正三角形ABC.如下接上:直线y=kx+b过点C,与x轴,y轴分别交于D,E,且DE平行于AB求线段OE及BD的长](/uploads/image/z/6689718-54-8.jpg?t=%E5%B7%B2%E7%9F%A5%E7%82%B9A%280%2C%E4%BA%8C%E5%88%86%E4%B9%8B%E6%A0%B9%E5%8F%B715%29%2CB%281%2F2%2C0%29%2C%E4%BB%A5%E7%BA%BF%E6%AE%B5AB%E4%B8%BA%E8%BE%B9%2C%E5%9C%A8%E7%AC%AC%E4%B8%80%E8%B1%A1%E9%99%90%E5%86%85%E4%BD%9C%E6%AD%A3%E4%B8%89%E8%A7%92%E5%BD%A2ABC.%E5%A6%82%E4%B8%8B%E6%8E%A5%E4%B8%8A%EF%BC%9A%E7%9B%B4%E7%BA%BFy%3Dkx%2Bb%E8%BF%87%E7%82%B9C%2C%E4%B8%8Ex%E8%BD%B4%2Cy%E8%BD%B4%E5%88%86%E5%88%AB%E4%BA%A4%E4%BA%8ED%2CE%2C%E4%B8%94DE%E5%B9%B3%E8%A1%8C%E4%BA%8EAB%E6%B1%82%E7%BA%BF%E6%AE%B5OE%E5%8F%8ABD%E7%9A%84%E9%95%BF)
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