等差数列{an}前n项和Sn,{bn}前n项和Tn,有Sn/Tn=(4n+1)/(3n-1) ,n为不为零的自然数,求g(x)=an/bn的解析式.我解的是先设Sn=m(4n+1),Tn=m(3n-1),所以a1=5m,b1=2m,因为Sn=n(a1+an)/2,所以an=2m(4n+1
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![等差数列{an}前n项和Sn,{bn}前n项和Tn,有Sn/Tn=(4n+1)/(3n-1) ,n为不为零的自然数,求g(x)=an/bn的解析式.我解的是先设Sn=m(4n+1),Tn=m(3n-1),所以a1=5m,b1=2m,因为Sn=n(a1+an)/2,所以an=2m(4n+1](/uploads/image/z/6698359-55-9.jpg?t=%E7%AD%89%E5%B7%AE%E6%95%B0%E5%88%97%EF%BD%9Ban%EF%BD%9D%E5%89%8Dn%E9%A1%B9%E5%92%8CSn%2C%EF%BD%9Bbn%EF%BD%9D%E5%89%8Dn%E9%A1%B9%E5%92%8CTn%2C%E6%9C%89Sn%2FTn%3D%EF%BC%884n%2B1%EF%BC%89%2F%EF%BC%883n-1%EF%BC%89+%2Cn%E4%B8%BA%E4%B8%8D%E4%B8%BA%E9%9B%B6%E7%9A%84%E8%87%AA%E7%84%B6%E6%95%B0%2C%E6%B1%82g%EF%BC%88x%EF%BC%89%3Dan%2Fbn%E7%9A%84%E8%A7%A3%E6%9E%90%E5%BC%8F.%E6%88%91%E8%A7%A3%E7%9A%84%E6%98%AF%E5%85%88%E8%AE%BESn%3Dm%EF%BC%884n%2B1%EF%BC%89%2CTn%3Dm%EF%BC%883n-1%EF%BC%89%2C%E6%89%80%E4%BB%A5a1%3D5m%2Cb1%3D2m%2C%E5%9B%A0%E4%B8%BASn%3Dn%EF%BC%88a1%2Ban%EF%BC%89%2F2%2C%E6%89%80%E4%BB%A5an%3D2m%EF%BC%884n%2B1)
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