在不等式组中确定实数a的取值范围,如题.比如说这个题 x/2+(x+1)/3>0x+(5a+4)/3>4/3(x+1)+a有两个整数解,求a的取值范围由 x/2+(x+1)/3>0,两边同乘以6得3x+2(x+1)>0,解得x>- 2/5,由x+(5a+4)/3>
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![在不等式组中确定实数a的取值范围,如题.比如说这个题 x/2+(x+1)/3>0x+(5a+4)/3>4/3(x+1)+a有两个整数解,求a的取值范围由 x/2+(x+1)/3>0,两边同乘以6得3x+2(x+1)>0,解得x>- 2/5,由x+(5a+4)/3>](/uploads/image/z/6766930-10-0.jpg?t=%E5%9C%A8%E4%B8%8D%E7%AD%89%E5%BC%8F%E7%BB%84%E4%B8%AD%E7%A1%AE%E5%AE%9A%E5%AE%9E%E6%95%B0a%E7%9A%84%E5%8F%96%E5%80%BC%E8%8C%83%E5%9B%B4%2C%E5%A6%82%E9%A2%98.%E6%AF%94%E5%A6%82%E8%AF%B4%E8%BF%99%E4%B8%AA%E9%A2%98+x%2F2%2B%28x%2B1%29%2F3%EF%BC%9E0x%2B%EF%BC%885a%2B4%EF%BC%89%2F3%EF%BC%9E4%2F3%EF%BC%88x%2B1%EF%BC%89%2Ba%E6%9C%89%E4%B8%A4%E4%B8%AA%E6%95%B4%E6%95%B0%E8%A7%A3%2C%E6%B1%82a%E7%9A%84%E5%8F%96%E5%80%BC%E8%8C%83%E5%9B%B4%E7%94%B1+x%2F2%2B%28x%2B1%29%2F3%EF%BC%9E0%2C%E4%B8%A4%E8%BE%B9%E5%90%8C%E4%B9%98%E4%BB%A56%E5%BE%973x%2B2%EF%BC%88x%2B1%EF%BC%89%EF%BC%9E0%2C%E8%A7%A3%E5%BE%97x%EF%BC%9E-+2%2F5%2C%E7%94%B1x%2B%EF%BC%885a%2B4%EF%BC%89%2F3%EF%BC%9E)
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