高一数学设向量a=(cos(α+β),sin(α+β))设向量a=(cos(α+β),sin(α+β)),b=(cos(α-β),sin(α-β),且a+b=(4/5,3/5).(1)求tanα(2)求2cos^2(α/2)-3sinα-1/根号2sin(α+π/4).
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![高一数学设向量a=(cos(α+β),sin(α+β))设向量a=(cos(α+β),sin(α+β)),b=(cos(α-β),sin(α-β),且a+b=(4/5,3/5).(1)求tanα(2)求2cos^2(α/2)-3sinα-1/根号2sin(α+π/4).](/uploads/image/z/6847819-43-9.jpg?t=%E9%AB%98%E4%B8%80%E6%95%B0%E5%AD%A6%E8%AE%BE%E5%90%91%E9%87%8Fa%3D%28cos%28%CE%B1%2B%CE%B2%29%2Csin%28%CE%B1%2B%CE%B2%29%29%E8%AE%BE%E5%90%91%E9%87%8Fa%3D%28cos%28%CE%B1%2B%CE%B2%29%2Csin%28%CE%B1%2B%CE%B2%29%29%2Cb%3D%28cos%28%CE%B1-%CE%B2%EF%BC%89%2Csin%28%CE%B1-%CE%B2%EF%BC%89%2C%E4%B8%94a%2Bb%3D%284%2F5%2C3%2F5%29.%EF%BC%881%EF%BC%89%E6%B1%82tan%CE%B1%EF%BC%882%EF%BC%89%E6%B1%822cos%5E2%28%CE%B1%2F2%EF%BC%89-3sin%CE%B1-1%2F%E6%A0%B9%E5%8F%B72sin%28%CE%B1%2B%CF%80%2F4%29.)
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