若4x^2+y^2-4x+6y+10=0,则x^y的值为?若4x^2+y^2-4x+6y+10=0,则x^y的值为( )
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![若4x^2+y^2-4x+6y+10=0,则x^y的值为?若4x^2+y^2-4x+6y+10=0,则x^y的值为( )](/uploads/image/z/6858479-47-9.jpg?t=%E8%8B%A54x%5E2%2By%5E2-4x%2B6y%2B10%3D0%2C%E5%88%99x%5Ey%E7%9A%84%E5%80%BC%E4%B8%BA%3F%E8%8B%A54x%5E2%2By%5E2-4x%2B6y%2B10%3D0%2C%E5%88%99x%5Ey%E7%9A%84%E5%80%BC%E4%B8%BA%EF%BC%88+%EF%BC%89)
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若4x^2+y^2-4x+6y+10=0,则x^y的值为?若4x^2+y^2-4x+6y+10=0,则x^y的值为( )
若4x^2+y^2-4x+6y+10=0,则x^y的值为?
若4x^2+y^2-4x+6y+10=0,则x^y的值为( )
若4x^2+y^2-4x+6y+10=0,则x^y的值为?若4x^2+y^2-4x+6y+10=0,则x^y的值为( )
即(4x²-4x+1)+(y²+6y+9)=0
(2x-1)²+(y+3)²=0
所以2x-1=y+3=0
x=1/2,y=-3
所以x^3=(1/2)^(-3)=8
4x^2+y^2-4x+6y+10=0,
(2x-1)²+(y+3)²=0
则必有:
2x-1=0
y+3=0
解得:x=1/2;y=-3
x^y=(1/2)^(-3)=8
4x^2+y^2-4x+6y+10=(2X-1)^2+(y^+3)^2=0,所以x=1/2,y=-3 所有x^y=8
原式可化为:(2x-1)^2+(y+3)^2=0
则:2x-1=0;y+3=0
则:x=1/2,y=-3
所以:x^y=(1/2)^(-3)=8
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