椭圆x^2/2+y^2=1及圆外一点M(0,2),过这点引直线与椭圆交于AB两点,求AB的中点P的轨迹方程详解~~~
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![椭圆x^2/2+y^2=1及圆外一点M(0,2),过这点引直线与椭圆交于AB两点,求AB的中点P的轨迹方程详解~~~](/uploads/image/z/6859826-26-6.jpg?t=%E6%A4%AD%E5%9C%86x%5E2%2F2%2By%5E2%3D1%E5%8F%8A%E5%9C%86%E5%A4%96%E4%B8%80%E7%82%B9M%280%2C2%29%2C%E8%BF%87%E8%BF%99%E7%82%B9%E5%BC%95%E7%9B%B4%E7%BA%BF%E4%B8%8E%E6%A4%AD%E5%9C%86%E4%BA%A4%E4%BA%8EAB%E4%B8%A4%E7%82%B9%2C%E6%B1%82AB%E7%9A%84%E4%B8%AD%E7%82%B9P%E7%9A%84%E8%BD%A8%E8%BF%B9%E6%96%B9%E7%A8%8B%E8%AF%A6%E8%A7%A3%7E%7E%7E)
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