如图已知直线AB与x轴交于点C,与双曲线y=k/x交于A(3,20/3)、B(-5,a)两点.AD⊥x轴于点D,BE//x轴且与y轴交点E.1.求点B的坐标及直线AB的解析式2.判断四边形CBED的形状,并说明理由
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![如图已知直线AB与x轴交于点C,与双曲线y=k/x交于A(3,20/3)、B(-5,a)两点.AD⊥x轴于点D,BE//x轴且与y轴交点E.1.求点B的坐标及直线AB的解析式2.判断四边形CBED的形状,并说明理由](/uploads/image/z/6877475-35-5.jpg?t=%E5%A6%82%E5%9B%BE%E5%B7%B2%E7%9F%A5%E7%9B%B4%E7%BA%BFAB%E4%B8%8Ex%E8%BD%B4%E4%BA%A4%E4%BA%8E%E7%82%B9C%2C%E4%B8%8E%E5%8F%8C%E6%9B%B2%E7%BA%BFy%3Dk%2Fx%E4%BA%A4%E4%BA%8EA%283%2C20%2F3%29%E3%80%81B%28-5%2Ca%29%E4%B8%A4%E7%82%B9.AD%E2%8A%A5x%E8%BD%B4%E4%BA%8E%E7%82%B9D%2CBE%2F%2Fx%E8%BD%B4%E4%B8%94%E4%B8%8Ey%E8%BD%B4%E4%BA%A4%E7%82%B9E.1.%E6%B1%82%E7%82%B9B%E7%9A%84%E5%9D%90%E6%A0%87%E5%8F%8A%E7%9B%B4%E7%BA%BFAB%E7%9A%84%E8%A7%A3%E6%9E%90%E5%BC%8F2.%E5%88%A4%E6%96%AD%E5%9B%9B%E8%BE%B9%E5%BD%A2CBED%E7%9A%84%E5%BD%A2%E7%8A%B6%2C%E5%B9%B6%E8%AF%B4%E6%98%8E%E7%90%86%E7%94%B1)
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