TAN(a+π/4)=1/2 -π/2＜A＜0 求(2SINA^2+SIN2A)/COS(A-π/4) 的值,

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TAN(a+π/4)=1/2 -π/2＜A＜0 求(2SINA^2+SIN2A)/COS(A-π/4) 的值,
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TAN(a+π/4)=1/2 -π/2＜A＜0 求(2SINA^2+SIN2A)/COS(A-π/4) 的值,
TAN(a+π/4)=1/2 -π/2＜A＜0 求(2SINA^2+SIN2A)/COS(A-π/4) 的值,

TAN(a+π/4)=1/2 -π/2＜A＜0 求(2SINA^2+SIN2A)/COS(A-π/4) 的值,
tan(A+π/4) =1/2
(tanA+1)/(1-tanA)=1/2
2tanA+2 =1-tanA
tanA= -1/3
sinA = -1/√10
cosA = 3/√10
sin2A = 2sinAcosA = -3/5
cos(A-π/4) = cosAcos(π/4)+sinAsin(π/4)
=(1/√2)(2/√10)
=1/√5
[2(sinA)^2+sin2A]/ cos(A-π/4)
=[2(1/10)-3/5]/(1/√5)
= -2√5/5

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