x方+1/x方-x+1/x-4=0解方程,

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x方+1/x方-x+1/x-4=0解方程,
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x方+1/x方-x+1/x-4=0解方程,
x方+1/x方-x+1/x-4=0解方程,

x方+1/x方-x+1/x-4=0解方程,
x²+1/x² -(x-1/x)-4=0
(x-1/x)²-(x-1/x)+2-4=0
设x-1/x=a则
a²-a-2=0
(a+1)(a-2)=0
a=-1 a=2
x-1/x=-1
x²+x-1=0
x= (-1±√5)/2
x-1/x= 2
x²-2x-1=0
(x-1)²-1-1=0
(x-1)²=2
x=1±√2
以上四个解就是这个方程的解!

x方+1/x方-x+1/x-4=0,
(x-1/x)^2+2-(x-1/x)-4=0,
(x-1/x)^2-(x-1/x)-2=0,
(x-1/x-2)(x-1/x+1)=0,
x-1/x-2=0,x-1/x+1=0,
当x-1/x-2=0,
x^2-2x-1=0,
x=1±√2
当x-1/x+1=0,
x^2+x-1=0,
x=(-1±√5)/2
检验:均为方程的根,所以共有四个根
楼上是对的! 谢谢你的提醒

x方+1/x方-x+1/x-4=0,
(x-1/x)^2+2-(x-1/x)-4=0,
(x-1/x)^2-(x-1/x)-2=0,
(x-1/x-2)(x-1/x+1)=0,
x-1/x-2=0,x-1/x+1=0,
当x-1/x-2=0,
x^2-2x-1=0,
x=1±√2
当x-1/x+1=0,
x^2+x-1=0,
x=(-1±√5)/2