将两块含30°角且大小相同的直角三角板如图一摆放.(1)将图一中△A1B1C1绕点C顺时针旋转45°得图二,P1是A1C1与AB的交点,求证:CP1=根号2/2 AP1.(2)若将图二中的△A1B1C1再绕点C顺时针旋转30°得图
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![将两块含30°角且大小相同的直角三角板如图一摆放.(1)将图一中△A1B1C1绕点C顺时针旋转45°得图二,P1是A1C1与AB的交点,求证:CP1=根号2/2 AP1.(2)若将图二中的△A1B1C1再绕点C顺时针旋转30°得图](/uploads/image/z/6922893-21-3.jpg?t=%E5%B0%86%E4%B8%A4%E5%9D%97%E5%90%AB30%C2%B0%E8%A7%92%E4%B8%94%E5%A4%A7%E5%B0%8F%E7%9B%B8%E5%90%8C%E7%9A%84%E7%9B%B4%E8%A7%92%E4%B8%89%E8%A7%92%E6%9D%BF%E5%A6%82%E5%9B%BE%E4%B8%80%E6%91%86%E6%94%BE.%EF%BC%881%EF%BC%89%E5%B0%86%E5%9B%BE%E4%B8%80%E4%B8%AD%E2%96%B3A1B1C1%E7%BB%95%E7%82%B9C%E9%A1%BA%E6%97%B6%E9%92%88%E6%97%8B%E8%BD%AC45%C2%B0%E5%BE%97%E5%9B%BE%E4%BA%8C%2CP1%E6%98%AFA1C1%E4%B8%8EAB%E7%9A%84%E4%BA%A4%E7%82%B9%2C%E6%B1%82%E8%AF%81%EF%BC%9ACP1%3D%E6%A0%B9%E5%8F%B72%2F2+AP1.%282%29%E8%8B%A5%E5%B0%86%E5%9B%BE%E4%BA%8C%E4%B8%AD%E7%9A%84%E2%96%B3A1B1C1%E5%86%8D%E7%BB%95%E7%82%B9C%E9%A1%BA%E6%97%B6%E9%92%88%E6%97%8B%E8%BD%AC30%C2%B0%E5%BE%97%E5%9B%BE)
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