高数 去微积分方程通解求微分方程(1+x²)y'=arctanx的通解解:(1+x²)(dy/dx)=arctanx,分离变量得:dy=[(arctanx)/(1+x²)]dx积分之,即得通解为:y=∫[(arctanx)/(1+x²)]dx=∫(arctanx)d(arctanx)=(1/2)(arc
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![高数 去微积分方程通解求微分方程(1+x²)y'=arctanx的通解解:(1+x²)(dy/dx)=arctanx,分离变量得:dy=[(arctanx)/(1+x²)]dx积分之,即得通解为:y=∫[(arctanx)/(1+x²)]dx=∫(arctanx)d(arctanx)=(1/2)(arc](/uploads/image/z/6923758-22-8.jpg?t=%E9%AB%98%E6%95%B0+%E5%8E%BB%E5%BE%AE%E7%A7%AF%E5%88%86%E6%96%B9%E7%A8%8B%E9%80%9A%E8%A7%A3%E6%B1%82%E5%BE%AE%E5%88%86%E6%96%B9%E7%A8%8B%281%2Bx%26%23178%3B%29y%26%2339%3B%3Darctanx%E7%9A%84%E9%80%9A%E8%A7%A3%E8%A7%A3%EF%BC%9A%281%2Bx%26%23178%3B%29%28dy%2Fdx%29%3Darctanx%2C%E5%88%86%E7%A6%BB%E5%8F%98%E9%87%8F%E5%BE%97%EF%BC%9Ady%3D%5B%28arctanx%29%2F%281%2Bx%26%23178%3B%29%5Ddx%E7%A7%AF%E5%88%86%E4%B9%8B%2C%E5%8D%B3%E5%BE%97%E9%80%9A%E8%A7%A3%E4%B8%BA%EF%BC%9Ay%3D%E2%88%AB%5B%28arctanx%29%2F%281%2Bx%26%23178%3B%29%5Ddx%3D%E2%88%AB%28arctanx%29d%28arctanx%29%3D%281%2F2%29%28arc)
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