【设参倒角】已知:如图,∠MAN为锐角,AD平分∠MAN,点B,点C分别在射线AM和AN上,AB=AC(1)若点E在线段CA上,线段EC的垂直平分线交直线AD于点F,直线BE交直线AD于点G,求证:∠EBF=∠CAG(2)若(1)中
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![【设参倒角】已知:如图,∠MAN为锐角,AD平分∠MAN,点B,点C分别在射线AM和AN上,AB=AC(1)若点E在线段CA上,线段EC的垂直平分线交直线AD于点F,直线BE交直线AD于点G,求证:∠EBF=∠CAG(2)若(1)中](/uploads/image/z/6941325-21-5.jpg?t=%E3%80%90%E8%AE%BE%E5%8F%82%E5%80%92%E8%A7%92%E3%80%91%E5%B7%B2%E7%9F%A5%EF%BC%9A%E5%A6%82%E5%9B%BE%2C%E2%88%A0MAN%E4%B8%BA%E9%94%90%E8%A7%92%2CAD%E5%B9%B3%E5%88%86%E2%88%A0MAN%2C%E7%82%B9B%2C%E7%82%B9C%E5%88%86%E5%88%AB%E5%9C%A8%E5%B0%84%E7%BA%BFAM%E5%92%8CAN%E4%B8%8A%2CAB%3DAC%EF%BC%881%EF%BC%89%E8%8B%A5%E7%82%B9E%E5%9C%A8%E7%BA%BF%E6%AE%B5CA%E4%B8%8A%2C%E7%BA%BF%E6%AE%B5EC%E7%9A%84%E5%9E%82%E7%9B%B4%E5%B9%B3%E5%88%86%E7%BA%BF%E4%BA%A4%E7%9B%B4%E7%BA%BFAD%E4%BA%8E%E7%82%B9F%2C%E7%9B%B4%E7%BA%BFBE%E4%BA%A4%E7%9B%B4%E7%BA%BFAD%E4%BA%8E%E7%82%B9G%2C%E6%B1%82%E8%AF%81%EF%BC%9A%E2%88%A0EBF%3D%E2%88%A0CAG%EF%BC%882%EF%BC%89%E8%8B%A5%EF%BC%881%EF%BC%89%E4%B8%AD)
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