z=x/[(x^2+y^2)^1/2] 的全微分dz需要具体过程 谢谢啦
来源:学生作业帮助网 编辑:作业帮 时间:2024/09/08 14:44:54
![z=x/[(x^2+y^2)^1/2] 的全微分dz需要具体过程 谢谢啦](/uploads/image/z/6949493-53-3.jpg?t=z%3Dx%2F%5B%28x%5E2%2By%5E2%29%5E1%2F2%5D+%E7%9A%84%E5%85%A8%E5%BE%AE%E5%88%86dz%E9%9C%80%E8%A6%81%E5%85%B7%E4%BD%93%E8%BF%87%E7%A8%8B+++%E8%B0%A2%E8%B0%A2%E5%95%A6)
x)Џ֨3Ү3Ҍ37Ux>i늧=hKz9ŲƧ۟b
/6,S$aXl䠧<ٱlцs5k**4u(:+mu+*xdRb)U$RؔJ<;P H
z=x/[(x^2+y^2)^1/2] 的全微分dz需要具体过程 谢谢啦
z=x/[(x^2+y^2)^1/2] 的全微分dz
需要具体过程 谢谢啦
z=x/[(x^2+y^2)^1/2] 的全微分dz需要具体过程 谢谢啦
因为
偏z/偏x=[1/(x^2+y^2)^(1/2)] - (x^2)(x^2+y^2)^(-3/2)
偏z/偏y=-xy(x^2+y^2)^(-3/2)
所以全微分
dz=[[1/(x^2+y^2)^(1/2)] - (x^2)(x^2+y^2)^(-3/2)]dx+[-xy(x^2+y^2)^(-3/2)]dy
1、y-x/x²-y²2、(x-y)(y-z)(z-x)/(z-y)(y-x)(x-z)
已知实数x y z满足x/(x+1)=y/(y+2)=z/(z+3)=(x+y+z)/3,求x+y+z的值
已知实数x y z满足x/(x+1)=y/(y+2)=z/(z+3)=(x+y+z)/3,求x+y+z的值
用行列式的性质证明:y+z z+x x+y x y z x+y y+z z+x =2 z x y z+x x+y y+z y z x 这个怎么证?
(x-2y+z)(x+y-2z)分之(y-x)(z-x) + (x+y-2z)(y+z-2x)分之(z-y)(x-y) + (y+z-2z)(x-2y+z)分之(x-z)(y-z)=?第三部分那个是 (y+z-2x)(x-2y+z)分之(x-z)(y-z)
x+y+z=6 x+2y+3z=14 y+1=z
试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y)
已知:x^2/(z+y)+y^2/(x+z)+z^2/(x+y)=0,求x/(z+y)+y/(x+z)+z/(x+y)的值.
x^2/(z+y)+y^2/(x+z)+z^2/(x+y)=0,求x/(z+y)+y/(x+z)+z/(x+y)的值
已知(x+y)(x+z)=x,(y+z)(y+x)=2y,(z+x)(z+y)=3z,求x,y,z
若|x+3|+|y-2|+|2×z+1|=0求(x×z-y×z)(y-x+z)的值
分式加减的几道题目求速度1 .(x+y)²/(x-z)(y-z) - (y+z)²/(x-z)(y-z) = 2.2x+3y/x-y+2y/y-x-3y/x-y=
matlab解对数方程组[x,y,z]=solve('0.29744*x/(3+0.1*x+y+z)=(log10((3+x+y+z)/(3+0.1*x+y+z)))^2','0.79*x/(3+0.1*y+z)=(log10((3+x+y+z)/(3+0.1*x+y+z)*(3+y+z)/(3+0.1*y+z)))^2','1.25*x/(3+0.1*z)=(log10((3+x+y+z)/(3+0.1*x+y+z)*(3+y+z)/(3+0.*1y+z)*(3+z)/
已知x,y,z>0,xyz(x+y+z)=1,求证(x+y)(x+z)>=2
X+2Y= -12X+Y+Z= 1-X+Y-Z= -1
X+y+z=26,x-y=1,2x-y+z=18
(x+y-z)^2-(x-y+z)^2=?
(x-y-z)*( )=x^2-(y+z)^2 填空