在三角形的边OA,OB上分别有一点P,Q,已知OP:PA=1:2,OQ:QB=3:2连接AQ,BP,设它们交于R,若OA=a,OB=b(1)用向量a和向量b表示向量OR.(2)过R作RH⊥AB,垂足为H,若|a|=1,|b|=2,向量a与向量b的夹角θ∈[π/3,2π/3]求|BH
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![在三角形的边OA,OB上分别有一点P,Q,已知OP:PA=1:2,OQ:QB=3:2连接AQ,BP,设它们交于R,若OA=a,OB=b(1)用向量a和向量b表示向量OR.(2)过R作RH⊥AB,垂足为H,若|a|=1,|b|=2,向量a与向量b的夹角θ∈[π/3,2π/3]求|BH](/uploads/image/z/6965419-67-9.jpg?t=%E5%9C%A8%E4%B8%89%E8%A7%92%E5%BD%A2%E7%9A%84%E8%BE%B9OA%2COB%E4%B8%8A%E5%88%86%E5%88%AB%E6%9C%89%E4%B8%80%E7%82%B9P%2CQ%2C%E5%B7%B2%E7%9F%A5OP%3APA%3D1%3A2%2COQ%3AQB%3D3%3A2%E8%BF%9E%E6%8E%A5AQ%2CBP%2C%E8%AE%BE%E5%AE%83%E4%BB%AC%E4%BA%A4%E4%BA%8ER%2C%E8%8B%A5OA%3Da%2COB%3Db%EF%BC%881%EF%BC%89%E7%94%A8%E5%90%91%E9%87%8Fa%E5%92%8C%E5%90%91%E9%87%8Fb%E8%A1%A8%E7%A4%BA%E5%90%91%E9%87%8FOR.%EF%BC%882%EF%BC%89%E8%BF%87R%E4%BD%9CRH%E2%8A%A5AB%2C%E5%9E%82%E8%B6%B3%E4%B8%BAH%2C%E8%8B%A5%7Ca%7C%3D1%2C%7Cb%7C%3D2%2C%E5%90%91%E9%87%8Fa%E4%B8%8E%E5%90%91%E9%87%8Fb%E7%9A%84%E5%A4%B9%E8%A7%92%CE%B8%E2%88%88%5B%CF%80%2F3%2C2%CF%80%2F3%5D%E6%B1%82%7CBH)
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