作业帮[sin4α/(1+cos4α)]×[cos2α/(1+cos2α)]×[cosα/(1+cosα)]=?
来源：学生作业帮助网 编辑：作业帮 时间：2024/11/30 10:10:55
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[sin4α/(1+cos4α)]×[cos2α/(1+cos2α)]×[cosα/(1+cosα)]=?
[sin4α/(1+cos4α)]×[cos2α/(1+cos2α)]×[cosα/(1+cosα)]=?
[sin4α/(1+cos4α)]×[cos2α/(1+cos2α)]×[cosα/(1+cosα)]=?
[sin4α/(1+cos4α)]×[cos2α/(1+cos2α)]×[cosα/(1+cosα)]=[2*2*[2sin(α/2)cos(α/2)]cosα/(2cos2α) ] × cos2α/[2(cosα)^2] × cosα/[2(cosα/2)^2]=tan(α/2)
化简√（1+sin8）的结果是：A、sin4+cos4 B、sin4-cos4 C、cos4-sin4 D、-sin4-cos4( )
证明：cot2α=(1+sin4α+cos4α)/(1+sin4α-cos4α)
化简1+sin4α+cos4α/1+sin4α -cos4α
化简(1-cos4α+sin4α)/(1+cos4α+sin4α)
1+cos4α+sin4α/1-cos4α+sin4α.怎么解
怎样化简(1+sin4α+cos4α)÷(1+sin4-cos4α)
化简cos4α/2-sin4α/2
sin4α cos4α等于多少
cos4次方α-sin4次方α=?,
(1+sin4θ-cos4θ)/(1+sin4θ+cos4θ)-(1+sin4θ+cos4θ)/(1+sin4θ-cos4θ)
[sin4α/(1+cos4α)]×[cos2α/(1+cos2α)]×[cosα/(1+cosα)]=?
证明：(1-cos4α)/sin4α*cos2α/(1+cos2α)=tanα
求证：[（1-cos4α）/sin4α]*[cos2α/(1+cos2α）]=tanα
求证cos4α*tan2α-sin4α=2tanα/tan方α-1
sin2α+cos2α=1,sin4α+cos4α为什么等于1
化简1-cos4α-sin4α/1-cos5α-sin6α（数字是次数,如图所示）
1sinα＋cosα＝根号2求sin4α-cos4α
cos4α×tan2α-sin4α=2tanα/(tan^2-1)过程!