∫(0→π)√(sin∧3 x-sin∧5 x)dx正确答案是4/5,如果令sinx=t,x=0→t=0,x=π,t=0,后面直接不用看,∫(0→0)=0有人说连续导数是导数无拐点,sinx导数cosx在[0,π]有拐点,不连续,不能用换元法?
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/21 05:40:24
![∫(0→π)√(sin∧3 x-sin∧5 x)dx正确答案是4/5,如果令sinx=t,x=0→t=0,x=π,t=0,后面直接不用看,∫(0→0)=0有人说连续导数是导数无拐点,sinx导数cosx在[0,π]有拐点,不连续,不能用换元法?](/uploads/image/z/7057716-60-6.jpg?t=%E2%88%AB%280%E2%86%92%CF%80%29%E2%88%9A%28sin%E2%88%A73+x-sin%E2%88%A75+x%29dx%E6%AD%A3%E7%A1%AE%E7%AD%94%E6%A1%88%E6%98%AF4%2F5%2C%E5%A6%82%E6%9E%9C%E4%BB%A4sinx%3Dt%2Cx%3D0%E2%86%92t%3D0%2Cx%3D%CF%80%2Ct%3D0%2C%E5%90%8E%E9%9D%A2%E7%9B%B4%E6%8E%A5%E4%B8%8D%E7%94%A8%E7%9C%8B%2C%E2%88%AB%280%E2%86%920%29%3D0%E6%9C%89%E4%BA%BA%E8%AF%B4%E8%BF%9E%E7%BB%AD%E5%AF%BC%E6%95%B0%E6%98%AF%E5%AF%BC%E6%95%B0%E6%97%A0%E6%8B%90%E7%82%B9%2Csinx%E5%AF%BC%E6%95%B0cosx%E5%9C%A8%5B0%2C%CF%80%5D%E6%9C%89%E6%8B%90%E7%82%B9%2C%E4%B8%8D%E8%BF%9E%E7%BB%AD%2C%E4%B8%8D%E8%83%BD%E7%94%A8%E6%8D%A2%E5%85%83%E6%B3%95%3F)
xTRA~9B\kÍ1*\%",*))JqKx߁r3ƔVk*gd>OwVooF2o":J"%/SMq^Iv#8k,dq;ː{b늯[/#XxD=/t; ]\[Cro32ۯcƝ! *wb_JY0nNLJ5'S_R]
1tFmE