sqrt(1-sin(4x))求0到pi/2上定积分
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sqrt(1-sin(4x))求0到pi/2上定积分
sqrt(1-sin(4x))求0到pi/2上定积分
sqrt(1-sin(4x))求0到pi/2上定积分
这道题需要讨论范围,所以拆开最好……
积分符号内式子sqrt(1-sin(4x))的化sqrt(sin2x-cos2x)^2,由于根号下的正负不同,所以化成从0到π/8的cos2x-sin2x的定积分加上π/8到π/2的sin2x-cos2x的定积分,这样就好求啦,最后结果为根号2
这道题重要的是根据定义域分成两部分,
sqrt(1-sin(4x))求0到pi/2上定积分
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