一道有关平行四边形的几何证明题如图,已知平行四边形ABCD中P为BC上一动点(不与B、C重合),连接PE,以PE、BE为边作平行四边形EBFP,连接CF,以CF、PF为边作平行四边形PFCG.求证:无论P点如何运动,
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![一道有关平行四边形的几何证明题如图,已知平行四边形ABCD中P为BC上一动点(不与B、C重合),连接PE,以PE、BE为边作平行四边形EBFP,连接CF,以CF、PF为边作平行四边形PFCG.求证:无论P点如何运动,](/uploads/image/z/7120996-52-6.jpg?t=%E4%B8%80%E9%81%93%E6%9C%89%E5%85%B3%E5%B9%B3%E8%A1%8C%E5%9B%9B%E8%BE%B9%E5%BD%A2%E7%9A%84%E5%87%A0%E4%BD%95%E8%AF%81%E6%98%8E%E9%A2%98%E5%A6%82%E5%9B%BE%2C%E5%B7%B2%E7%9F%A5%E5%B9%B3%E8%A1%8C%E5%9B%9B%E8%BE%B9%E5%BD%A2ABCD%E4%B8%ADP%E4%B8%BABC%E4%B8%8A%E4%B8%80%E5%8A%A8%E7%82%B9%EF%BC%88%E4%B8%8D%E4%B8%8EB%E3%80%81C%E9%87%8D%E5%90%88%EF%BC%89%2C%E8%BF%9E%E6%8E%A5PE%2C%E4%BB%A5PE%E3%80%81BE%E4%B8%BA%E8%BE%B9%E4%BD%9C%E5%B9%B3%E8%A1%8C%E5%9B%9B%E8%BE%B9%E5%BD%A2EBFP%2C%E8%BF%9E%E6%8E%A5CF%2C%E4%BB%A5CF%E3%80%81PF%E4%B8%BA%E8%BE%B9%E4%BD%9C%E5%B9%B3%E8%A1%8C%E5%9B%9B%E8%BE%B9%E5%BD%A2PFCG.%E6%B1%82%E8%AF%81%EF%BC%9A%E6%97%A0%E8%AE%BAP%E7%82%B9%E5%A6%82%E4%BD%95%E8%BF%90%E5%8A%A8%2C)
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