lim n→∞ [(n+1)^4/5^(n+1)]/[n^4/5^n]为何等于1/5,

用数列极限证明lim(n→∞)(n^-2)/(n^+n+1)=1中证明如下:lim(n→∞)3n+1/5n-4 lim n→∞ [(n+1)^4/5^(n+1)]/[n^4/5^n]为何等于1/5, lim((5^n-4^(n-1))/((5^(n+1)+3^(n+2)) n→∞时的极限是多少? 求lim(n→∞)时[5^n-4^(n-1)]/5^(n+1)+3^(n+2) lim {（-4）^n+5^n}/{4^(n+1) + 5^(n+1)} n→无限 求极限 lim(n→∞) tan^n (π/4 + 2/n) lim(n→∞)tan^n(π/4+2/n) =lim(n→∞)[(tan(π/4)+tan(2/n))/(1-tan(π/4)tan(2/n))]^n =lim(n→∞)[(1+tan(2/n))/(1-tan(2/n))]^n =lim(n→∞)(1+tan(2/n))^n/(1-tan(2/n))^n (1) 因为 lim(n→∞)(1+tan(2/n) 计算下列极限：1）lim(n→∞) 1/n3 2）lim(n→∞)4n+1/3n-11）lim(n→∞) 1/n3 2）lim(n→∞)4n+1/3n-13) lim(n→∞) (1/3)n4)lim(n→∞)n3+2n-5/5n3-n 5) lim(n→∞)(1+1/2n)n 6) lim(n→∞)2x3-x2+1/3x2+2x-9 7) lim(x→0 )sin3x/sin7x8) lim(n→∞)3n^2+5n-7/4-n^2的值是 求当n→∞,Lim(1+2+3+4+……+(n-1)+n)/n 大一微积分解答：lim(n→+∞)（2^n+4^n+6^n+8^n）^1/n=? lim[n→∞] (x^n+1)^(1/n) 求lim n→∞ (1+2/n)^n+3 lim(n→∞)[1-(2n/n+3)] lim(n→∞)(2n-1/n+3) 求 lim (n→+∞) n^( 1/n)的极限 lim(arctan n)^1/n (n→∞)求极值 lim（1/n）sin n （n→∞） lim(n→∞) 1/(n+1)-2/(n+1)+3/(n+1)-4/(n+1)+...+[(2n-1)/(n+1)]-[(2n)/(n-1)]求极限