设f是定义在(-∞,0)∪(0,+∞)上的函数,f(x)满足:f(xy)=f(x)+f(y),且f(x)是区间(0,∞)上的递增函数.1.求f(1),f(-1)的值:2.求证f(x)是偶函数:3.解不等式f(2)+f(x-2/1)
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![设f是定义在(-∞,0)∪(0,+∞)上的函数,f(x)满足:f(xy)=f(x)+f(y),且f(x)是区间(0,∞)上的递增函数.1.求f(1),f(-1)的值:2.求证f(x)是偶函数:3.解不等式f(2)+f(x-2/1)](/uploads/image/z/7170293-29-3.jpg?t=%E8%AE%BEf%E6%98%AF%E5%AE%9A%E4%B9%89%E5%9C%A8%28-%E2%88%9E%2C0%29%E2%88%AA%280%2C%2B%E2%88%9E%29%E4%B8%8A%E7%9A%84%E5%87%BD%E6%95%B0%2Cf%28x%29%E6%BB%A1%E8%B6%B3%3Af%28xy%29%3Df%28x%29%2Bf%28y%29%2C%E4%B8%94f%28x%29%E6%98%AF%E5%8C%BA%E9%97%B4%280%2C%E2%88%9E%EF%BC%89%E4%B8%8A%E7%9A%84%E9%80%92%E5%A2%9E%E5%87%BD%E6%95%B0.1.%E6%B1%82f%EF%BC%881%EF%BC%89%2Cf%EF%BC%88-1%EF%BC%89%E7%9A%84%E5%80%BC%EF%BC%9A2.%E6%B1%82%E8%AF%81f%EF%BC%88x%EF%BC%89%E6%98%AF%E5%81%B6%E5%87%BD%E6%95%B0%EF%BC%9A3.%E8%A7%A3%E4%B8%8D%E7%AD%89%E5%BC%8Ff%EF%BC%882%EF%BC%89%2Bf%EF%BC%88x-2%2F1%EF%BC%89)
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