就是求特征值和特征向量时那个基础解系的问题例如:求矩阵3 2 4A=2 0 24 2 3的特征值和特征向量矩阵A的特征多项式λ -3 -2 -4λ I-A= -2 λ -2 = ( λ +1)的二次方( λ -8)-4 -2 λ -3中间的省略一点,
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![就是求特征值和特征向量时那个基础解系的问题例如:求矩阵3 2 4A=2 0 24 2 3的特征值和特征向量矩阵A的特征多项式λ -3 -2 -4λ I-A= -2 λ -2 = ( λ +1)的二次方( λ -8)-4 -2 λ -3中间的省略一点,](/uploads/image/z/7219395-27-5.jpg?t=%E5%B0%B1%E6%98%AF%E6%B1%82%E7%89%B9%E5%BE%81%E5%80%BC%E5%92%8C%E7%89%B9%E5%BE%81%E5%90%91%E9%87%8F%E6%97%B6%E9%82%A3%E4%B8%AA%E5%9F%BA%E7%A1%80%E8%A7%A3%E7%B3%BB%E7%9A%84%E9%97%AE%E9%A2%98%E4%BE%8B%E5%A6%82%EF%BC%9A%E6%B1%82%E7%9F%A9%E9%98%B53+2+4A%3D2+0+24+2+3%E7%9A%84%E7%89%B9%E5%BE%81%E5%80%BC%E5%92%8C%E7%89%B9%E5%BE%81%E5%90%91%E9%87%8F%E7%9F%A9%E9%98%B5A%E7%9A%84%E7%89%B9%E5%BE%81%E5%A4%9A%E9%A1%B9%E5%BC%8F%CE%BB+-3+-2+-4%CE%BB+I-A%3D+-2+%CE%BB+-2+%3D+%EF%BC%88+%CE%BB+%2B1%EF%BC%89%E7%9A%84%E4%BA%8C%E6%AC%A1%E6%96%B9%EF%BC%88+%CE%BB+-8%EF%BC%89-4+-2+%CE%BB+-3%E4%B8%AD%E9%97%B4%E7%9A%84%E7%9C%81%E7%95%A5%E4%B8%80%E7%82%B9%2C)
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