∫[1/(sin^2(x)cos^4(x)]dx

∫[1/(sin^2(x)cos^4(x)]dx 求解∫1/(cos^4(x)sin^2(x))dx 化简[1-(sin^4x-sin^2cos^2x+cos^4x)/(sin^2)]+3sin^2x 求证（cos^2 x-sin^2 x)(cos^4 x+sin^4 x)+1/4 sin 2x sin 4x=cos 2x 化简(sin x+cos x-1)(sin x-cos x+1)/sin 2x (1-(sin^4x-sin^2xcos^2x+cos^4x)/sin^2x +3sin^2x 化简[1-(sin^4 x-sin^2 xcos^2 x+cos^4 x)]/(sin^2 x)+3sin^2 x 证明一个sin&cos的等式证明 1+sin^2(x)+sin^4(x)+sin^6(x)=[1-sin^8(x)]/[cos^2(x)] 2cos x (sin x -cos x)+1 化简sin^4x-sin^2x+cos^2x 化简:sin^4 x-sin^2 x+cos^2 x ∫sin(x) cos^2(x)dx 化简sin^4x+cos^2x 求证(3-sin^4 x-cos^4 x)/2cos^2 x=1+tan^2 x+sin^2 x 化简(sin^2x-cos^4x+cos^2x-sin^4x)/(sin^2x-cos^6x+cos^2x-sin^6x) cos x/sin x+sin x/(1+cos x) 化简. 求∫1/(sin^4x+cos^4x)dx, ∫dx/cos^2X+4sin^2X