作业帮0.2∧2,log2∧0.2 ,2∧0.2三个数之间的大小关系为,
来源：学生作业帮助网 编辑：作业帮 时间：2024/11/15 04:54:35
x)33zԱH''? rt';:Xl';_N|V%˟nںOvұI*ҧ;*"@{g~qAb ^ x}
0.2∧2,log2∧0.2 ,2∧0.2三个数之间的大小关系为,
0.2∧2,log2∧0.2 ,2∧0.2三个数之间的大小关系为,
0.2∧2,log2∧0.2 ,2∧0.2三个数之间的大小关系为,
0.2^2=0.41
log2^0.2＜0
log2^0.2
2∧log2 1/3等于多少
解对数方程log2 (9∧x-4)=log2 (3∧x-2)+3
0.2∧2,log2∧0.2 ,2∧0.2三个数之间的大小关系为,
log2（log2∧16）怎样算?
求值:log2∧5×log5∧1/2
2∧(1-1/2log2(5))=?
y=log2∧（-4）怎么解,一定要详细过程谢谢.用换底公式解答，如y=log2∧（-1/2）=log2∧1 右上方-2∧（-1）=？
log2 SQR(7/48)+log2 12 -1/2log2 42
log2 SQR(7/48)+log2 12 -1/2log2 48
log2^(4^7*2^5)+log2^6-log2^3
(log2 9)/(log2 8) = 2/3(log2 3)
log2 3乘以log2 3等于2log2
比较对数大小 log1/2^0.2和log2^0.2
(log2)^2+(log5)^2+log2*log25
求(log2 5+log4 0.2)(log5 2+log25 0.5)
(log2^5+log4^0.2)(log5^2+log25^0.25)化简
|[log2(x)]^2-3log2(x)+1|
化简：(log2(x/4))*(log2(x/2))