已知圆C:X^2+(y-1)^2=5,直线l:mx-y+1-m=0,设l与圆c交于A,B两点,若定点p(1,1)分弦AB为AP/PB=2分之一,求L方程
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![已知圆C:X^2+(y-1)^2=5,直线l:mx-y+1-m=0,设l与圆c交于A,B两点,若定点p(1,1)分弦AB为AP/PB=2分之一,求L方程](/uploads/image/z/7310719-55-9.jpg?t=%E5%B7%B2%E7%9F%A5%E5%9C%86C%EF%BC%9AX%5E2%2B%28y-1%29%5E2%3D5%2C%E7%9B%B4%E7%BA%BFl%3Amx-y%2B1-m%3D0%2C%E8%AE%BEl%E4%B8%8E%E5%9C%86c%E4%BA%A4%E4%BA%8EA%2CB%E4%B8%A4%E7%82%B9%2C%E8%8B%A5%E5%AE%9A%E7%82%B9p%281%2C1%29%E5%88%86%E5%BC%A6AB%E4%B8%BAAP%2FPB%3D2%E5%88%86%E4%B9%8B%E4%B8%80%2C%E6%B1%82L%E6%96%B9%E7%A8%8B)
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