作业帮若x/3=y/4=z/5,则x+2y+3z/2x的值为初一下
来源：学生作业帮助网 编辑：作业帮 时间：2024/11/27 10:23:23
xN@_!!Jt{nKkE8q 43QӀV
7o&32g|T x%cNWӗiu\L \F֝~A1:U-Iσ29Q(~'NxX N{1L!\uzCILIjXZBːX8`@kl,Ƃ@vfFGPYbh9Jp/}- 3NHX2I($0oO\}}Έuuh%ƊUbJN{:-g\jV+8Y/o4@}3}%J i))X"TƸ M]K@ӭ/OF
若x/3=y/4=z/5,则x+2y+3z/2x的值为初一下
若x/3=y/4=z/5,则x+2y+3z/2x的值为
初一下
若x/3=y/4=z/5,则x+2y+3z/2x的值为初一下
设x/3=y/4=z/5 =t
x=3t
y=4t
z=5t
所以
x+2y+3z/2x
=3t+2*(4t)+3*(5t) / 2*3t
=26t/6t
=13/3
x/3=y/4=z/5=k
x=3k, y=4k, z=5k
(x+2y+3z)/x
=(3k+8k+15k)/3k
=26/3
若x/2=y/3=z/4,则3x-2y+5z/x+y+z=
若x+y+z=3y=2z,则x/x+y+z=?
若x/2=y/3=z/4则3x-2y+5z/x+y+x=
已知：4x-5y+2z=0 x+4y-3z=0则：(x*x+y*y+z*z)/(x*y+y*z+z*x)=____.
(4x-2y-z)-{5x-[8y-2z-(x-2y)]-x-(3y-10z)}=?
三元一次方程组题目x+y-z=11 y+z-x=5 x-y+z=1x+y=4 y+z=3 x+z=5若已知x-3y+2z=0 2x+3y-8z=0, 且xyz≠0,则x:y:z=
若x/3=y/4=z/5则x+y/x-2y+3z=?
若x/4=y/4=z/5,则x+y/x-2y+3z=
若2x+5y+4z=0 ,3x+y=0；则x+y-z=?
若3x+7y+z=5,4x+10y+z=3,则x+y+z=?
若x/3=y/2=z/5,则2x-3y-z/x-y+z=
已知(x+2y)/3=(y+3z)/4=(z+5x)/5,则x:y:z=
已知x+2y/3=y+3z/4=z+5x/5,则x:y:z=?
已知x+2y/3=y+3z/4=z+5x/5,则x:y:z=
若2x=3y=5z,则3x-2y+z/x+y-z
若x+y:y+z:z+x=3:4:5,则x:y:z=?(急,)
若x/3=y/4=z/5,求x+y+z/3x-2y+z的值.
已知2x+5y+4z=15.7x+y+3z=14 则x+y+z=?