若A=1*2*3*4...*99*100,则A的尾部有多少个连续的零拜托各位了 3Q

a=-1 求a-2a+3a-4a+5a-6a+...+99a-100a 当a=1时,a-2a+3a-4a+5a…+99a-100a= 化简多项式a-2a+3a-4a+5a-...+99a-100a用下面方法解决 a-(a+b)+(a+2b)-(a+3b)+...-(a+101b)解法1：a-2a+3a-4a+5a-..+99a-100a =(a+3a+5a+..+99a)+(-2a-4a-6a-...-100a)=2500a-2550a=-50a解法2：a-2a+3a-4a+5a-...+99a-100a=(a-2a)+(3a-4a)+(5a-6a)+.. 当a=1时,求a-2a+3a-4a+...+99a-100a的值 a-2a+3a-4a+5a-6a+7a-8a+9a-10a+11a.+99a-100a= 当a=1时,a-2a+3a-4a+AA+99a-100a的值是A:5050 B:100 C:50 D:-50 化简 a-2a+3a-4a+5a'''''''+99a-100a a=-2 的值 a-2a+3a-4a+.99a-100a= 若（3x-1)=a^0+a^1x^1+a^2x^2+……+a^5x^5 1.a^0+a^1+a^2+a^3+a^4+a^5=?2.a^0-a^1+a^2-a^3+a^4-a^5=?3.a^0+a^2+a^4=?4.a^1+a^3+a^5=?5.a^0=? 当A=-3时,A-2A+3A-4A+``````+99A-100A的值是多少?当A=-3时,A-2A+3A-4A+````````````+99A-100A的值是多少? a-2a+3a-4a+5a-6a+...+99a-100a 已知A=a+a^1+a^2+a^3+...+a^2012,若a=1,则A=____________；若a=-1,则A=______________. 1/(a-1)+1/(a-1)(a-2)+1(a-2)(a-3).1/(a-99)(a-100) A=a+a^1+a^2+a^3+...+a^2008,若a等于1,则A等于【 】;若a=-1,则A=[ 若a+b=1,求代数式a+2a+3a+...+100a+b+2b+3b+... A=｛a+2,（a+1)²,a²+3a+3｝若1∈A 求a的值 已集合A=｛a+2,（a+1),a+3a+3｝,若1∈A,求a 【1】a+a=a×a a= [ ]【2】a×a=a÷a a=[ ]【3】a×a=a－a a=[ ] [4]a－a=a＋a a=[ ]