已知:2/2x4=1/2-1/4 .计算:2/2x4+2/4x6+2/6x8+2/8x10+2/10x2
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已知:2/2x4=1/2-1/4 .计算:2/2x4+2/4x6+2/6x8+2/8x10+2/10x2
已知:2/2x4=1/2-1/4 .计算:2/2x4+2/4x6+2/6x8+2/8x10+2/10x2
已知:2/2x4=1/2-1/4 .计算:2/2x4+2/4x6+2/6x8+2/8x10+2/10x2
2/2x4+2/4x6+2/6x8+2/8x10+2/10x12
=1/2-1/4+1/4-1/6+1/6-1/8+1/8-1/10+1/10-1/12
=1/2-1/12
=6/12-1/12
=5/12
2/2x4+2/4x6+2/6x8+2/8x10+2/10x12
=1/2-1/4 +1/4-1/6 +1/6-1/8 +1/8-1/10 +1/10-1/12
=1/2-1/12
=5/12
2/2x4+2/4x6+2/6x8+2/8x10+2/10x2=1/2-1/4+1/4-1/6+1/6-1/8+1/8-1/10+1/10=1/2
已知X+X分之1=2,求X4+X4分之1的值
已知1/2x3=1/2-1/3,1/3x4=1/3-1/4,.计算1/2x3+1/3x4+1/4x5+1/5x6.
已知:2/2x4=1/2-1/4 .计算:2/2x4+2/4x6+2/6x8+2/8x10+2/10x2
已知二分之一减四分之一=2x4分之2,计算2x4分之1+4x6分之1+6x8分之1+8x10分之1+10x12分之1
100x100-99x99+98x98-97x97+.+4x4-x4-3x3+2x2-1计算
x+1/x=2 求x2+1/x2 x4+1/x4 的值x2+1/x2 x4+1/x4 2和4是平方。
1x2+2x3+3x4=3分2x(3x4)+3分3x(3x4)=3分3x4x5规律计算2008x2009分之1x(1x2+2x3+3x4+.+2008x2009)
|-2x4-3|怎样计算
线性代数中求基础解系时自由未知变量是不是任取比如现在通过计算将方程组变为x1=(2*x3)+(3*x4) x2=(5*x3)+(4*x4)我看书上将x1,x2选为主元,选x3,x4为自由未知量,然后令x3,x4=1,0与x3,x4=0,1,代入x1=(2*x3)+(3
x1-x2+x3=1x2-x3+x4=21若x1,x2,x3,x4,x5满足方程组 x3-x4+x5=3x4-x5+x1=4x5-x1+x2=5求x2 x3 x4的值2已知 x1+x4+x6+x7=39 x2+x4+x5+x7=49 x3+x5+x6+x7=41 x4+x7=13 x5+x7=14 x6+x7=9 x1+x2+x3+x4+x5+x6+x7=9求x7的值若x1,x2,x3,x4,x5满足方程组 x1-x
6x+4(2x-1)+3x4(45-3x4)=171
用克拉默法则解下列方程组 x1-2x2+3x3-4x4=4 x2-x3+x4=-3 x1+3x2+2x4=1 -7x2+3x3+x4=3x1-2x2+3x3-4x4=4x2-x3+x4=-3 x1+3x2+2x4=1 -7x2+3x3+x4=3
已知x+1/x=4,求(1)x2+1/x2的值,(2)x4+1/x4的值x的后面是次方
已知x+x-1=a,求x2+x-2和x4+x-4的值
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简便计算1/2+1/2x3+1/3x4+1/4x5+...+1/99x100
计算:1/1x2+1/2x3+1/3X4+...+1/9x10=?
计算:1/1x2+1/2x3+1/3X4+...+1/9x10=?