(31+1/3)*(41+1/2)-(11+1/3)*(41+1/2)*2-(9+1/2)*(11+1/3)
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/29 06:45:13
x)0667014u5Dt5,!,MR>Zl(זD
3#%҆jEmdPlj&iadmhkjfkhnkdjd_\g
pJ
(31+1/3)*(41+1/2)-(11+1/3)*(41+1/2)*2-(9+1/2)*(11+1/3)
(31+1/3)*(41+1/2)-(11+1/3)*(41+1/2)*2-(9+1/2)*(11+1/3)
(31+1/3)*(41+1/2)-(11+1/3)*(41+1/2)*2-(9+1/2)*(11+1/3)
=(31+1/3)*(41+1/2)-(11+1/3)*(41+1/2)-(11+1/3)*(41+1/2)-(9+1/2)*(11+1/3)
=[(31+1/3)-(11+1/3)]*(41+1/2)-[(41+1/2)+(9+1/2)]*(11+1/3)
=20*(41+1/2)-51*(11+1/3)
=820+10-561-17=252
(31+1/3)*(41+1/2)-(11+1/3)*(41+1/2)*2-(9+1/2)*(11+1/3)
31 1/3*41 1/2 -11 1/3*41 1/2*2-9 1/2*11 1/3
简便计算?51 2/3+41 1/3*3/4+31 1/2*2/3
简便运算:31又1/3×41又1/2-11又1/3×41又1/2×2-9.5×11又1/3
简便运算:31又1/3×41又1/2-11又1/3×41又1/2×2-9.5×11又1/3
31又1/3×41又1/2-11又1/3×41又1/2×2-9.5×11又1/3
有理数的加减乘除混合运算 ⑴31又1/3 × 41又1/2 - 11又1/3 × 41又1/2 × 2 - 9.5 × 11又1/3
51又2/3*3/5+41又1/3*3/4+31又1/2*2/3=?
找规律填数1( )2 61 3 41 4 31( )( )6 21
简便计算?71 1/6*6/7+61 1/5*5/6+51 1/4*4/5+41 1/3*3/4+31 1/2*2/3
31又2分之1*3分之1+41又3分之1*4分之1+51又4分之1*5分之1 简便运算
用matlab求矩阵特征值和特征向量A=[1 5 1 3 31/5 1 6 4 21 1/6 1 3 41/3 1/4 1/3 1 21/3 1/2 1/4 1/2 1]
求特征向量和特征根1 1/3 4 3 33 1 6 4 41/4 1/6 1 1/3 1/31/3 1/4 3 1 11/3 1/4 2 1 1 五乘五的矩阵
31又3/1乘以41又2/1减11又3/1乘以41又2/1乘以2 减9又2/1乘以11又3/1
计算 (1/11+1/21+1/31+1/41)*(1/21+1/31+1/41+1/51)-(1/11+1/21+1/31+1/41+1/51)*(1/21+1/31+1/41)
(1/11+1/21+1/31+1/41)*(1/21+1/31+1/41+1/51)-(1/11+1/21+1/31+1/41+1/51)*(1/21+1/31+1/41)老师要方法啊.
(1/11+1/21+1/31++1/41)*(1/21+1/31++1/41+1/51)-(1/11+1/21+1/31+1/41+1/51)*(1/21+1/31+1/41)=?
(1/11+1/21+1/31+1/41)*(1/21+1/31+1/41+1/51)-(1/11+1/21+1/31+1/41+/51)*(1/21+1/31+1/41)