f(x)=x^2-+x-1复合函数求f[f(lnx)]=(ln^2x+lnx-1)^2+(ln^2x+lnx-1)-1怎么算到=ln^4x+2ln^3x-lnx-1求详细

来源:学生作业帮助网 编辑:作业帮 时间:2024/11/30 10:00:47
f(x)=x^2-+x-1复合函数求f[f(lnx)]=(ln^2x+lnx-1)^2+(ln^2x+lnx-1)-1怎么算到=ln^4x+2ln^3x-lnx-1求详细
x)KӨд3ծ5|鄎{MlcSZtFN^f-3rt 5㌴Qxnӎ @) m# e\ V4ew$F;%T0XӁ6|:$5l"{,bM;~Eg

f(x)=x^2-+x-1复合函数求f[f(lnx)]=(ln^2x+lnx-1)^2+(ln^2x+lnx-1)-1怎么算到=ln^4x+2ln^3x-lnx-1求详细
f(x)=x^2-+x-1复合函数求f[f(lnx)]=(ln^2x+lnx-1)^2+(ln^2x+lnx-1)-1怎么算到=ln^4x+2ln^3x-lnx-1求详细

f(x)=x^2-+x-1复合函数求f[f(lnx)]=(ln^2x+lnx-1)^2+(ln^2x+lnx-1)-1怎么算到=ln^4x+2ln^3x-lnx-1求详细
f[f(lnx)]
=(ln^2x+lnx-1)^2+(ln^2x+lnx-1)-1
=(ln^2x+lnx-1)(ln^2x+lnx-1+1)-1
=(ln^2x+lnx-1)(ln^2x+lnx)-1
=ln^4x+ln^3x-ln^2x+ln^3x+ln^2x-lnx-1
=ln^4x+2ln^3x-lnx-1
请点击下面的【选为满意回答】按钮,