线段AB=1,点C在线段AB上,以AC为半径的圆A与以CB为半径的圆C相交于点D,BD的延长线与圆A相交于点E,CD、AE的的延长线相交于点F,求证:(1)角ADB=3角B(2)设圆C的半径为a,EF的长为y,求y与a 的函数解
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![线段AB=1,点C在线段AB上,以AC为半径的圆A与以CB为半径的圆C相交于点D,BD的延长线与圆A相交于点E,CD、AE的的延长线相交于点F,求证:(1)角ADB=3角B(2)设圆C的半径为a,EF的长为y,求y与a 的函数解](/uploads/image/z/7670212-52-2.jpg?t=%E7%BA%BF%E6%AE%B5AB%3D1%2C%E7%82%B9C%E5%9C%A8%E7%BA%BF%E6%AE%B5AB%E4%B8%8A%2C%E4%BB%A5AC%E4%B8%BA%E5%8D%8A%E5%BE%84%E7%9A%84%E5%9C%86A%E4%B8%8E%E4%BB%A5CB%E4%B8%BA%E5%8D%8A%E5%BE%84%E7%9A%84%E5%9C%86C%E7%9B%B8%E4%BA%A4%E4%BA%8E%E7%82%B9D%2CBD%E7%9A%84%E5%BB%B6%E9%95%BF%E7%BA%BF%E4%B8%8E%E5%9C%86A%E7%9B%B8%E4%BA%A4%E4%BA%8E%E7%82%B9E%2CCD%E3%80%81AE%E7%9A%84%E7%9A%84%E5%BB%B6%E9%95%BF%E7%BA%BF%E7%9B%B8%E4%BA%A4%E4%BA%8E%E7%82%B9F%2C%E6%B1%82%E8%AF%81%EF%BC%9A%EF%BC%881%EF%BC%89%E8%A7%92ADB%3D3%E8%A7%92B%EF%BC%882%EF%BC%89%E8%AE%BE%E5%9C%86C%E7%9A%84%E5%8D%8A%E5%BE%84%E4%B8%BAa%2CEF%E7%9A%84%E9%95%BF%E4%B8%BAy%2C%E6%B1%82y%E4%B8%8Ea+%E7%9A%84%E5%87%BD%E6%95%B0%E8%A7%A3)
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