AB=CD,DF⊥AC于F,BE⊥AC于E,DF=BE.试说明:AF=CE

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AB=CD,DF⊥AC于F,BE⊥AC于E,DF=BE.试说明:AF=CE
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AB=CD,DF⊥AC于F,BE⊥AC于E,DF=BE.试说明:AF=CE
AB=CD,DF⊥AC于F,BE⊥AC于E,DF=BE.试说明:AF=CE

AB=CD,DF⊥AC于F,BE⊥AC于E,DF=BE.试说明:AF=CE
∵∠DFC=∠AEB=90°
且AB=CD,DF=EB
∴根据勾股定理 AE=CF
∵AE-EF=CF-FE
∴AF=CE