在直角坐标平面内,已知点A(3,0)B(0,3)C(cosθ,sinθ),θ∈(π/2,3π/2)若向量丨AC丨=向量丨BC丨,求角θ的弧度数2.若向量AC*BC=-1,求2sin²θ-sin2θ/1+tanθ的值
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![在直角坐标平面内,已知点A(3,0)B(0,3)C(cosθ,sinθ),θ∈(π/2,3π/2)若向量丨AC丨=向量丨BC丨,求角θ的弧度数2.若向量AC*BC=-1,求2sin²θ-sin2θ/1+tanθ的值](/uploads/image/z/8441677-37-7.jpg?t=%E5%9C%A8%E7%9B%B4%E8%A7%92%E5%9D%90%E6%A0%87%E5%B9%B3%E9%9D%A2%E5%86%85%2C%E5%B7%B2%E7%9F%A5%E7%82%B9A%283%2C0%29B%280%2C3%29C%28cos%CE%B8%2Csin%CE%B8%29%2C%CE%B8%E2%88%88%EF%BC%88%CF%80%2F2%2C3%CF%80%2F2%EF%BC%89%E8%8B%A5%E5%90%91%E9%87%8F%E4%B8%A8AC%E4%B8%A8%3D%E5%90%91%E9%87%8F%E4%B8%A8BC%E4%B8%A8%2C%E6%B1%82%E8%A7%92%CE%B8%E7%9A%84%E5%BC%A7%E5%BA%A6%E6%95%B02.%E8%8B%A5%E5%90%91%E9%87%8FAC%2ABC%3D-1%2C%E6%B1%822sin%26sup2%3B%CE%B8-sin2%CE%B8%2F1%2Btan%CE%B8%E7%9A%84%E5%80%BC)
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