ΔABC的顶点A(1,4),AB边上的高所在的直线方程为x+y-1=0,AC边上的中线所在方程为x-2y=0,球BC边所在的方
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![ΔABC的顶点A(1,4),AB边上的高所在的直线方程为x+y-1=0,AC边上的中线所在方程为x-2y=0,球BC边所在的方](/uploads/image/z/8576630-62-0.jpg?t=%CE%94ABC%E7%9A%84%E9%A1%B6%E7%82%B9A%EF%BC%881%2C4%EF%BC%89%2CAB%E8%BE%B9%E4%B8%8A%E7%9A%84%E9%AB%98%E6%89%80%E5%9C%A8%E7%9A%84%E7%9B%B4%E7%BA%BF%E6%96%B9%E7%A8%8B%E4%B8%BAx%2By-1%3D0%2CAC%E8%BE%B9%E4%B8%8A%E7%9A%84%E4%B8%AD%E7%BA%BF%E6%89%80%E5%9C%A8%E6%96%B9%E7%A8%8B%E4%B8%BAx-2y%3D0%2C%E7%90%83BC%E8%BE%B9%E6%89%80%E5%9C%A8%E7%9A%84%E6%96%B9)
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