(2+1)(4+1)(16+1)(256+1)怎么算?
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/19 09:39:47
![(2+1)(4+1)(16+1)(256+1)怎么算?](/uploads/image/z/8592029-53-9.jpg?t=%282%2B1%29%284%2B1%29%2816%2B1%29%28256%2B1%29%E6%80%8E%E4%B9%88%E7%AE%97%3F)
x)060f D=k{6IED/!4[
#]VP&$f8d<]tA3SSc(~ںu/.}Ɏ';Vt=:O'BlΧ=m]tOIIi$m_\g
ݬxx
(2+1)(4+1)(16+1)(256+1)怎么算?
(2+1)(4+1)(16+1)(256+1)怎么算?
(2+1)(4+1)(16+1)(256+1)怎么算?
=(2-1)(2+1)(4+1)(16+1)(256+1)
=(4-1)(4+1)(16+1)(256+1)
=(16-1)(16+1)(256+1)
=(256-1)(256+1)
=65536-1
=65535
关键补上一个(2-1),凑一个平方差公式,即(a+b)(a-b)=a平方-b平方
(2+1)(4+1)(16+1)(256+1)怎么算?
1/2+1/4+1/8+1/16+1/32+1/64+1/128+1/256
1/2-1/4-1/8-16/1-32/1-64/1-128/1-256/1
(1+1/2)(1+1/4)(1+1/16)(1+1/256) 等于多少?快
1/2-1/4-1/8-1/16-1/32-1/64-1/128-1/256
(1+1/2)(1+1/4)(1+1/16)(1+1/256) 等于多少?
1/2+1/4+1/8+1/16+1/32+1/64+1/128+1/256
初一(1+1/2)(1+1/4)(1+1/16)(1+1/256)(1-1/2)*(1+1/2)*(1+1/4)*(1+1/16))*(1+1/256)/(1-1/2)=(1-1/256*1/256)/(1-1/2)=2-2/256*256
(x-1/2)(2x+1)(2x^2+1/2)(4x^4+1/4)(16x^6+1/16)/(256x^16-1/256)
(x-1/2)(2x+1)(2x^2+1/2)(4x^4+1/4)(16x^8+1/16)÷(256x^16+1/256)=?
(x-1/2)(2x+1)(2x^2+1/2)(4x^4+1/4)(16x^6+1/16)/(256x^16+1/256)=?
计算:1/2+1/4+1/8+1/16+1/64+1/128+1/256
1-1/2-1/4-1/8-1/16-1/32-.1/256
利用平方差公式计算:(1+1/2)×(1+1/4)×(1+1/16)×(1/256)
1+1/2+1/4+1/8+1/16+1/32.+1/256 ?
简便计算1/2+1/4+1/8+1/16+.+1/128+1/256
1/2+1/4+1/8+1/16+1/32+...+1/256简便运算
1/2+1/4+1/8+1/16+1/32+...+1/256简便运算