(2x÷0.5)x2-2x=24
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![(2x÷0.5)x2-2x=24](/uploads/image/z/8598452-68-2.jpg?t=%282x%C3%B70.5%29x2-2x%3D24)
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(2x÷0.5)x2-2x=24
(2x÷0.5)x2-2x=24
(2x÷0.5)x2-2x=24
2x÷0.5)x2-2x=24
4x*2-2x=24
6x=24
x=4
(2x÷0.5)x2-2x=24
x2-2x-24
DIvide x3+x2-14x-24 by x+2Solution x2-x-12/)x-2)x3+x2-14x-24x3+2x/-2x2-14x-x2-2x/-12x-24-12x-24/0In this example we see that x+2 is a factor of x3+x2-14x-24,as the remainder is zero.Thus x3+x2-14x-24÷(x+2)=x2-x-12 with zero remainderso x3+x2-14x
4x-(6-2x)x2=24,求x
3/x2 -3x+2-1/x-2=1/x2 -x+4/x2 -2x
解方程:(x2-3x+2)(x2+3x-2)=x2(x+3)(x-3)
(x2-3x+2) (x2+3x-2)=x2(x+3)(x-3)解方程
化简x-1分之x+1-x2-1分之x2-2x÷x2-x-2/x2+2x+1
①x/(x2-1) ·(x2+x)/x2其中x=2 ②(x2-1)/(x2+4x+4)÷(x+1).(x+2﹚/﹙1-x﹚其中x=-3
x2+y2+x+y=18 x2+y2-2x-4x=24 解方程组
(x2-3x)2-x(x2-3x)-2x2
先化简,再求值 x+3/x2-1 ÷(x+3)(x-1)/x2-2x+1,其中x=2007,
[x2+2x]2-11[x2+2x]+24 因式分解
(3x2-x)2-3(3x2-x)=2
因式分解(x2+x+1)(x2+x+2)-12=
解方程(x2+x)(x2+x-2)=-1
2( x2 +1/x2) - 9( x + 1/x) + 14 =
解方程:X2--1/8(X2+2X)+X2+2X/3(X2--1)=11