将正方形ABCD绕中心O顺时针旋转角α得到正方形A1B1C1D1.如图1所示.(1)当α=45°时,如图2,若线段OA与边A1D1的交点为E.线段OA1与AB的交点为F.可得下列结论成立:1.△EOP全等△FOP 2.PA=PA1 .试选一个证
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![将正方形ABCD绕中心O顺时针旋转角α得到正方形A1B1C1D1.如图1所示.(1)当α=45°时,如图2,若线段OA与边A1D1的交点为E.线段OA1与AB的交点为F.可得下列结论成立:1.△EOP全等△FOP 2.PA=PA1 .试选一个证](/uploads/image/z/8600444-44-4.jpg?t=%E5%B0%86%E6%AD%A3%E6%96%B9%E5%BD%A2ABCD%E7%BB%95%E4%B8%AD%E5%BF%83O%E9%A1%BA%E6%97%B6%E9%92%88%E6%97%8B%E8%BD%AC%E8%A7%92%CE%B1%E5%BE%97%E5%88%B0%E6%AD%A3%E6%96%B9%E5%BD%A2A1B1C1D1.%E5%A6%82%E5%9B%BE1%E6%89%80%E7%A4%BA.%EF%BC%881%EF%BC%89%E5%BD%93%CE%B1%3D45%C2%B0%E6%97%B6%2C%E5%A6%82%E5%9B%BE2%2C%E8%8B%A5%E7%BA%BF%E6%AE%B5OA%E4%B8%8E%E8%BE%B9A1D1%E7%9A%84%E4%BA%A4%E7%82%B9%E4%B8%BAE.%E7%BA%BF%E6%AE%B5OA1%E4%B8%8EAB%E7%9A%84%E4%BA%A4%E7%82%B9%E4%B8%BAF.%E5%8F%AF%E5%BE%97%E4%B8%8B%E5%88%97%E7%BB%93%E8%AE%BA%E6%88%90%E7%AB%8B%EF%BC%9A1.%E2%96%B3EOP%E5%85%A8%E7%AD%89%E2%96%B3FOP+2.PA%3DPA1+.%E8%AF%95%E9%80%89%E4%B8%80%E4%B8%AA%E8%AF%81)
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