若x^2-2x+10+y^2+6y=0,求(2x+y)^2的值

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若x^2-2x+10+y^2+6y=0,求(2x+y)^2的值
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若x^2-2x+10+y^2+6y=0,求(2x+y)^2的值
若x^2-2x+10+y^2+6y=0,求(2x+y)^2的值

若x^2-2x+10+y^2+6y=0,求(2x+y)^2的值
紫静如,您好
x^2-2x+10+y^2+6y=0
(x-1)^2+(y+3)^2=0
x=1 y=-3
(2x+y)^2
=(2*1-3)^2
=1


x^2-2x+10+y^2+6y=0
x^2-2x+1+y^2+6y+9=0
(x-1)^2+(y+3)^=0
x-1=0
y+3=0
x=1
y=-3
(2x+y)^2=(2-3)^2=1

x²+2x+y²-6y+10=0
(x+1)²+(y-3)²=0
得x=-1,y=3